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Comb Sort Algorithm Assignment Help


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What is Comb Sort Algorithm?


1) Comb sort improves on bubble sort by using gap of size more than 1.

2) The gap starts with a large value and shrinks by a factor of 1.3 in every iteration until it reaches the value 1.


EXAMPLE: To start with we have the following array: 4 6 2 3 7 1 8 0 9 5


Iteration 1: Gap : 8

Input
4
6
2
3
7
1
8
0
9
5

Index 0 with index8- we find the elements in order, hence no swap needed.



4
6
2
3
7
1
8
0
9
5

Index 1 with index 9 – we find the elements not in order, hence swap needed. 


Iteration 2:- Gap : 6

Input
4
5
2
3
7
1
8
0
9
6

Index 0 with index 6 – we find the elements in order, hence no swap needed.



4
5
2
3
7
1
8
0
9
6

Index 1 with index 7 – we find the elements not in order, hence swap needed. 



4
0
2
3
7
1
8
0
9
6

Index 2 with index 8 – we find the elements in order, hence no swap needed.



4
0
2
3
7
1
8
5
9
6

Index 3 with index 9 – we find the elements in order, hence no swap needed.


RESULT
4
0
2
3
7
1
8
5
9
6


Iteration 3:- Gap : 4

Input
4
0
2
3
7
1
8
5
9
6

Index 0 with index 4 – we find the elements in order, hence no swap needed.



4
0
2
3
7
1
8
5
9
6

Index 1 with index 5 – we find the elements in order, hence no swap needed.



4
0
2
3
7
1
8
5
9
6

Index 2 with index 6 – we find the elements in order, hence no swap needed.



4
0
2
3
7
1
8
5
9
6

Index 3 with index 7 – we find the elements in order, hence no swap needed.



4
0
2
3
7
1
8
5
9
6

Index 4 with index 8 – we find the elements in order, hence no swap needed.



4
0
2
3
7
1
8
5
9
6

Index 5 with index 9 – we find the elements in order, hence no swap needed.


RESULT
4
0
2
3
7
1
8
5
9
6


Iteration 4:- Gap : 3

Input
4
0
2
3
7
1
8
5
9
6

Index 0 with index 3- we find the elements not in order, hence swap needed. 



3
0
2
4
7
1
8
5
9
6

Index 1 with index 4 – we find the elements in order, hence no swap needed.



3
0
2
4
7
1
8
5
9
6

Index 2 with index 5 – we find the elements not in order, hence swap needed. 



3
0
1
4
7
2
8
5
9
6

Index 3 with index 6 – we find the elements in order, hence no swap needed.



3
0
1
4
7
2
8
5
9
6

Index 4 with index 7- we find the elements not in order, hence swap needed. 



3
0
1
4
5
2
8
7
9
6

Index 5 with index 8 – we find the elements in order, hence no swap needed.



3
0
1
4
5
2
8
7
9
6

Index 6 with index 9 – we find the elements not in order, hence swap needed.

RESULT
3
0
1
4
5
2
6
7
9
8



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